What are the solutions to the equation roots x^3+x^2-x-1 ?

The solutions to the equation roots x^3+x^2-x-1 are x=-1,x=1

Find the zeros of roots x^3+x^2-x-1

The zeros of roots x^3+x^2-x-1 are x=-1,x=1

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roots

x^{3} + x^{2} - x - 1

x = - 1, x = 1

Solution steps

x^{3} + x^{2} - x - 1

The roots are the intercepts with the x-axis

(y = 0)

x^{3} + x^{2} - x - 1 = 0

Factor

x^{3} + x^{2} - x - 1 : (x + 1)^{2} (x - 1)

(x + 1)^{2} (x - 1) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x + 1 = 0 or x - 1 = 0

Solve

x + 1 = 0 : x = - 1

Solve

x - 1 = 0 : x = 1

The solutions are

x = - 1, x = 1

x^{4} - x^{3} - 2 x - 4 = 0

x^{3} + 4 x + 4 = 0

x^{4} + 14 x^{3} + 77 x^{2} + 200 x + 208 = 0

3 x^{2} - 4 x + 2 = x^{3} - x

2.5 x^{4} + 3 x^{3} - 2.6 x^{2} - 5.1 x - 5.6

What are the solutions to the equation roots x^3+x^2-x-1 ?
The solutions to the equation roots x^3+x^2-x-1 are x=-1,x=1
Find the zeros of roots x^3+x^2-x-1
The zeros of roots x^3+x^2-x-1 are x=-1,x=1