What are the solutions to the equation 2(x-x^2)(1-2x)=0 ?

The solutions to the equation 2(x-x^2)(1-2x)=0 are x=0,x=1,x= 1/2

Find the zeros of 2(x-x^2)(1-2x)=0

The zeros of 2(x-x^2)(1-2x)=0 are x=0,x=1,x= 1/2

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2 (x - x^{2}) (1 - 2 x) = 0

x = 0, x = 1, x = \frac{1}{2}

Decimal Notation

x = 0, x = 1, x = 0.5

Solution steps

2 (x - x^{2}) (1 - 2 x) = 0

Factor

2 (x - x^{2}) (1 - 2 x) : 2 x (x - 1) (2 x - 1)

2 x (x - 1) (2 x - 1) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x = 0 or x - 1 = 0 or 2 x - 1 = 0

Solve

x - 1 = 0 : x = 1

Solve

2 x - 1 = 0 : x = \frac{1}{2}

The solutions are

x = 0, x = 1, x = \frac{1}{2}

x^{3} + 3 x + 8 = 0

x^{3} - 2 x^{2} - 5 x + 6 = 0

p^{4} + 40 = 14 p^{2}

m^{4} + m^{3} + m^{2} = 0

x^{3} + 3 x^{2} - 24 x - 72 = 0

What are the solutions to the equation 2(x-x^2)(1-2x)=0 ?
The solutions to the equation 2(x-x^2)(1-2x)=0 are x=0,x=1,x= 1/2
Find the zeros of 2(x-x^2)(1-2x)=0
The zeros of 2(x-x^2)(1-2x)=0 are x=0,x=1,x= 1/2