What are the solutions to the equation x^3+3x^2-24x-72=0 ?

The solutions to the equation x^3+3x^2-24x-72=0 are x=-3,x=-2sqrt(6),x=2sqrt(6)

Find the zeros of x^3+3x^2-24x-72=0

The zeros of x^3+3x^2-24x-72=0 are x=-3,x=-2sqrt(6),x=2sqrt(6)

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x^{3} + 3 x^{2} - 24 x - 72 = 0

x = - 3, x = - 26, x = 26

Decimal Notation

x = - 3, x = - 4.89897 \dots, x = 4.89897 \dots

Solution steps

x^{3} + 3 x^{2} - 24 x - 72 = 0

Factor

x^{3} + 3 x^{2} - 24 x - 72 : (x + 3) (x + 26) (x - 26)

(x + 3) (x + 26) (x - 26) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x + 3 = 0 or x + 26 = 0 or x - 26 = 0

Solve

x + 3 = 0 : x = - 3

Solve

x + 26 = 0 : x = - 26

Solve

x - 26 = 0 : x = 26

The solutions are

x = - 3, x = - 26, x = 26

5 x^{3} + x^{2} - 20 x - 4 = 0

10 x^{4} - 20 x^{3} - 30 x^{2} = 0

6 x^{2} - 2 x^{3} = 0

x^{3} - 5 x^{2} - 9 x + 45 = 0

x^{4} + 170 x^{2} + 169 = 0

What are the solutions to the equation x^3+3x^2-24x-72=0 ?
The solutions to the equation x^3+3x^2-24x-72=0 are x=-3,x=-2sqrt(6),x=2sqrt(6)
Find the zeros of x^3+3x^2-24x-72=0
The zeros of x^3+3x^2-24x-72=0 are x=-3,x=-2sqrt(6),x=2sqrt(6)