What are the solutions to the equation roots 4x^4-25x^2+36=0 ?

The solutions to the equation roots 4x^4-25x^2+36=0 are x=2,x=-2,x= 3/2 ,x=-3/2

Find the zeros of roots 4x^4-25x^2+36=0

The zeros of roots 4x^4-25x^2+36=0 are x=2,x=-2,x= 3/2 ,x=-3/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

roots

4 x^{4} - 25 x^{2} + 36 = 0

x = 2, x = - 2, x = \frac{3}{2}, x = - \frac{3}{2}

Solution steps

4 x^{4} - 25 x^{2} + 36 = 0

Rewrite the equation with

u = x^{2}

and

u^{2} = x^{4}

4 u^{2} - 25 u + 36 = 0

Solve

4 u^{2} - 25 u + 36 = 0 : u = 4, u = \frac{9}{4}

u = 4, u = \frac{9}{4}

Substitute back

u = x^{2},

solve for

x

Solve

x^{2} = 4 : x = 2, x = - 2

Solve

x^{2} = \frac{9}{4} : x = \frac{3}{2}, x = - \frac{3}{2}

The solutions are

x = 2, x = - 2, x = \frac{3}{2}, x = - \frac{3}{2}

x^{3} - 2 x + 2

x^{4} - 13 x^{2} + 36 = 0

x^{5} + 10 x + 3 = 0

2 x^{4} + 9 x^{3} - 87 x^{2} - 49 x + 45 = 0

x^{3} - 6 x^{2} + 61 x - 106 = 0

What are the solutions to the equation roots 4x^4-25x^2+36=0 ?
The solutions to the equation roots 4x^4-25x^2+36=0 are x=2,x=-2,x= 3/2 ,x=-3/2
Find the zeros of roots 4x^4-25x^2+36=0
The zeros of roots 4x^4-25x^2+36=0 are x=2,x=-2,x= 3/2 ,x=-3/2