What are the solutions to the equation 2x^4+9x^3-87x^2-49x+45=0 ?

The solutions to the equation 2x^4+9x^3-87x^2-49x+45=0 are x=-1,x=5,x= 1/2 ,x=-9

Find the zeros of 2x^4+9x^3-87x^2-49x+45=0

The zeros of 2x^4+9x^3-87x^2-49x+45=0 are x=-1,x=5,x= 1/2 ,x=-9

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

2 x^{4} + 9 x^{3} - 87 x^{2} - 49 x + 45 = 0

x = - 1, x = 5, x = \frac{1}{2}, x = - 9

Decimal Notation

x = - 1, x = 5, x = 0.5, x = - 9

Solution steps

2 x^{4} + 9 x^{3} - 87 x^{2} - 49 x + 45 = 0

Factor

2 x^{4} + 9 x^{3} - 87 x^{2} - 49 x + 45 : (x + 1) (x - 5) (2 x - 1) (x + 9)

(x + 1) (x - 5) (2 x - 1) (x + 9) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x + 1 = 0 or x - 5 = 0 or 2 x - 1 = 0 or x + 9 = 0

Solve

x + 1 = 0 : x = - 1

Solve

x - 5 = 0 : x = 5

Solve

2 x - 1 = 0 : x = \frac{1}{2}

Solve

x + 9 = 0 : x = - 9

The solutions are

x = - 1, x = 5, x = \frac{1}{2}, x = - 9

x^{3} - 6 x^{2} + 61 x - 106 = 0

x^{3} - 9 x - 12 = 0

x^{4} + 2 x^{3} - 5 x^{2} - 8 x + 4 = 0

x^{4} + 40 = 14 x^{2}

z^{3} = (1 - 3 i)

What are the solutions to the equation 2x^4+9x^3-87x^2-49x+45=0 ?
The solutions to the equation 2x^4+9x^3-87x^2-49x+45=0 are x=-1,x=5,x= 1/2 ,x=-9
Find the zeros of 2x^4+9x^3-87x^2-49x+45=0
The zeros of 2x^4+9x^3-87x^2-49x+45=0 are x=-1,x=5,x= 1/2 ,x=-9