What are the solutions to the equation z^3=(1-sqrt(3)i) ?

The solutions to the equation z^3=(1-sqrt(3)i) are

Find the zeros of z^3=(1-sqrt(3)i)

The zeros of z^3=(1-sqrt(3)i) are

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z^{3} = (1 - 3 i)

Solution steps

z^{3} = (1 - 3 i)

Remove parentheses:

(a) = a

z^{3} = 1 - 3 i

For

z^{n} = a

the solutions are

k = 0, 1, \dots, n - 1

For

n = 3, a = 1 - 3 i

∣ a ∣ = 2

ar g (a) = - \frac{π}{3}

Simplify

- x^{3} + 4 x^{2} - 5 x + 2

x^{4} - 4 x^{3} + 8 x^{2} - 16 x + 16

- 1 = m^{3}

x^{4} + 6 x^{3} + 17 x^{2} + 22 x + 14 = 0

x^{3} - 4 x - 8 = 0

What are the solutions to the equation z^3=(1-sqrt(3)i) ?
The solutions to the equation z^3=(1-sqrt(3)i) are
Find the zeros of z^3=(1-sqrt(3)i)
The zeros of z^3=(1-sqrt(3)i) are