What are the solutions to the equation -1=m^3 ?

The solutions to the equation -1=m^3 are m=-1,m= 1/2-(sqrt(3))/2 i,m= 1/2+(sqrt(3))/2 i

Find the zeros of -1=m^3

The zeros of -1=m^3 are m=-1,m= 1/2-(sqrt(3))/2 i,m= 1/2+(sqrt(3))/2 i

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- 1 = m^{3}

m = - 1, m = \frac{1}{2} - \frac{3}{2} i, m = \frac{1}{2} + \frac{3}{2} i

Solution steps

- 1 = m^{3}

Switch sides

m^{3} = - 1

For

x^{3} = f (a)

the solutions are

Simplify

m = - 1, m = \frac{1}{2} - \frac{3}{2} i, m = \frac{1}{2} + \frac{3}{2} i

x^{4} + 6 x^{3} + 17 x^{2} + 22 x + 14 = 0

x^{3} - 4 x - 8 = 0

x^{3} - 3 x^{2} - 4 x + 12

2 x^{3} - 3 x^{2} - 32 x + 48 = 0

x^{5} = x

What are the solutions to the equation -1=m^3 ?
The solutions to the equation -1=m^3 are m=-1,m= 1/2-(sqrt(3))/2 i,m= 1/2+(sqrt(3))/2 i
Find the zeros of -1=m^3
The zeros of -1=m^3 are m=-1,m= 1/2-(sqrt(3))/2 i,m= 1/2+(sqrt(3))/2 i