What are the solutions to the equation x^4-3x^3+3x^2-3x+2=0 ?

The solutions to the equation x^4-3x^3+3x^2-3x+2=0 are x=1,x=2,x=i,x=-i

Find the zeros of x^4-3x^3+3x^2-3x+2=0

The zeros of x^4-3x^3+3x^2-3x+2=0 are x=1,x=2,x=i,x=-i

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x^{4} - 3 x^{3} + 3 x^{2} - 3 x + 2 = 0

x = 1, x = 2, x = i, x = - i

Solution steps

x^{4} - 3 x^{3} + 3 x^{2} - 3 x + 2 = 0

Factor

x^{4} - 3 x^{3} + 3 x^{2} - 3 x + 2 : (x - 1) (x - 2) (x^{2} + 1)

(x - 1) (x - 2) (x^{2} + 1) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x - 1 = 0 or x - 2 = 0 or x^{2} + 1 = 0

Solve

x - 1 = 0 : x = 1

Solve

x - 2 = 0 : x = 2

Solve

x^{2} + 1 = 0 : x = i, x = - i

The solutions are

x = 1, x = 2, x = i, x = - i

x^{4} + 6 x^{3} - 3 x^{2} - 24 x - 4 = 0

x^{4} - 6 x^{3} + 2 x^{2} + 26 x + 17

9 x^{3} + 9 x^{2} - x - 1 = 0

4 x^{3} - 2 x^{2} - 14 x - 48

x^{5} - 6 x^{4} + 10 x^{3} - 6 x^{2} + 9 x = 0

What are the solutions to the equation x^4-3x^3+3x^2-3x+2=0 ?
The solutions to the equation x^4-3x^3+3x^2-3x+2=0 are x=1,x=2,x=i,x=-i
Find the zeros of x^4-3x^3+3x^2-3x+2=0
The zeros of x^4-3x^3+3x^2-3x+2=0 are x=1,x=2,x=i,x=-i