What are the solutions to the equation 9x^3+9x^2-x-1=0 ?

The solutions to the equation 9x^3+9x^2-x-1=0 are x=-1,x=-1/3 ,x= 1/3

Find the zeros of 9x^3+9x^2-x-1=0

The zeros of 9x^3+9x^2-x-1=0 are x=-1,x=-1/3 ,x= 1/3

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9 x^{3} + 9 x^{2} - x - 1 = 0

x = - 1, x = - \frac{1}{3}, x = \frac{1}{3}

Decimal Notation

x = - 1, x = - 0.33333 \dots, x = 0.33333 \dots

Solution steps

9 x^{3} + 9 x^{2} - x - 1 = 0

Factor

9 x^{3} + 9 x^{2} - x - 1 : (x + 1) (3 x + 1) (3 x - 1)

(x + 1) (3 x + 1) (3 x - 1) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x + 1 = 0 or 3 x + 1 = 0 or 3 x - 1 = 0

Solve

x + 1 = 0 : x = - 1

Solve

3 x + 1 = 0 : x = - \frac{1}{3}

Solve

3 x - 1 = 0 : x = \frac{1}{3}

The solutions are

x = - 1, x = - \frac{1}{3}, x = \frac{1}{3}

4 x^{3} - 2 x^{2} - 14 x - 48

x^{5} - 6 x^{4} + 10 x^{3} - 6 x^{2} + 9 x = 0

2 x^{3} + 7 x^{2} - 2 x - 7 = 0

4 x^{3} - 6 x^{2} - 1 = 0

x^{3} + x^{2} - 6 = 0

What are the solutions to the equation 9x^3+9x^2-x-1=0 ?
The solutions to the equation 9x^3+9x^2-x-1=0 are x=-1,x=-1/3 ,x= 1/3
Find the zeros of 9x^3+9x^2-x-1=0
The zeros of 9x^3+9x^2-x-1=0 are x=-1,x=-1/3 ,x= 1/3