What are the solutions to the equation x^3-6x^2+10x-4=0 ?

The solutions to the equation x^3-6x^2+10x-4=0 are x=2,x=2+sqrt(2),x=2-sqrt(2)

Find the zeros of x^3-6x^2+10x-4=0

The zeros of x^3-6x^2+10x-4=0 are x=2,x=2+sqrt(2),x=2-sqrt(2)

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x^{3} - 6 x^{2} + 10 x - 4 = 0

x = 2, x = 2 + 2, x = 2 - 2

Decimal Notation

x = 2, x = 3.41421 \dots, x = 0.58578 \dots

Solution steps

x^{3} - 6 x^{2} + 10 x - 4 = 0

Factor

x^{3} - 6 x^{2} + 10 x - 4 : (x - 2) (x^{2} - 4 x + 2)

(x - 2) (x^{2} - 4 x + 2) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x - 2 = 0 or x^{2} - 4 x + 2 = 0

Solve

x - 2 = 0 : x = 2

Solve

x^{2} - 4 x + 2 = 0 : x = 2 + 2, x = 2 - 2

The solutions are

x = 2, x = 2 + 2, x = 2 - 2

x^{4} - 7 x^{2} - 44 = 0

n^{3} - n = 4 n^{2} - 4

(x^{2} + 2)^{2} = 0

4 x^{3} + 12 x^{2} = x + 3

(6 x^{4}) + (6 x^{1}) = x (4 + 1)

What are the solutions to the equation x^3-6x^2+10x-4=0 ?
The solutions to the equation x^3-6x^2+10x-4=0 are x=2,x=2+sqrt(2),x=2-sqrt(2)
Find the zeros of x^3-6x^2+10x-4=0
The zeros of x^3-6x^2+10x-4=0 are x=2,x=2+sqrt(2),x=2-sqrt(2)