What are the solutions to the equation (x^2+2)^2=0 ?

The solutions to the equation (x^2+2)^2=0 are x=sqrt(2)i,x=-sqrt(2)i

Find the zeros of (x^2+2)^2=0

The zeros of (x^2+2)^2=0 are x=sqrt(2)i,x=-sqrt(2)i

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(x^{2} + 2)^{2} = 0

x = 2 i, x = - 2 i

Solution steps

(x^{2} + 2)^{2} = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

Solve

x^{2} + 2 = 0 : x = 2 i, x = - 2 i

The solutions are

x = 2 i, x = - 2 i

4 x^{3} + 12 x^{2} = x + 3

(6 x^{4}) + (6 x^{1}) = x (4 + 1)

x^{3} - 4 x^{2} + 5 x = 0

x^{6} + 18 x^{3} + 81

x^{4} - 2 x^{3} + 3 x^{2} - 2 x + 1 = 0

What are the solutions to the equation (x^2+2)^2=0 ?
The solutions to the equation (x^2+2)^2=0 are x=sqrt(2)i,x=-sqrt(2)i
Find the zeros of (x^2+2)^2=0
The zeros of (x^2+2)^2=0 are x=sqrt(2)i,x=-sqrt(2)i