What are the solutions to the equation n^3-n=6n^2-6 ?

The solutions to the equation n^3-n=6n^2-6 are n=6,n=-1,n=1

Find the zeros of n^3-n=6n^2-6

The zeros of n^3-n=6n^2-6 are n=6,n=-1,n=1

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

n^{3} - n = 6 n^{2} - 6

n = 6, n = - 1, n = 1

Solution steps

n^{3} - n = 6 n^{2} - 6

Move

6

to the left side

n^{3} - n + 6 = 6 n^{2}

Move

6 n^{2}

to the left side

n^{3} - n + 6 - 6 n^{2} = 0

Write in the standard form

a_{n} x^{n} + \dots + a_{1} x + a_{0} = 0

n^{3} - 6 n^{2} - n + 6 = 0

Factor

n^{3} - 6 n^{2} - n + 6 : (n - 6) (n + 1) (n - 1)

(n - 6) (n + 1) (n - 1) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

n - 6 = 0 or n + 1 = 0 or n - 1 = 0

Solve

n - 6 = 0 : n = 6

Solve

n + 1 = 0 : n = - 1

Solve

n - 1 = 0 : n = 1

The solutions are

n = 6, n = - 1, n = 1

x^{3} + 13 x^{2} + 40 x + 36 = 0

3 x^{3} + 5 x^{2} + 10 x - 4 = 0

90 x^{8} (1 - x) = 0.75

36 x^{3} + 45 x^{2} - 7 x - 4 = 0

x^{5} + 3 x - 4 = 0

What are the solutions to the equation n^3-n=6n^2-6 ?
The solutions to the equation n^3-n=6n^2-6 are n=6,n=-1,n=1
Find the zeros of n^3-n=6n^2-6
The zeros of n^3-n=6n^2-6 are n=6,n=-1,n=1