What are the solutions to the equation 3x^3-22x^2+5x+14=0 ?

The solutions to the equation 3x^3-22x^2+5x+14=0 are x=1,x=-2/3 ,x=7

Find the zeros of 3x^3-22x^2+5x+14=0

The zeros of 3x^3-22x^2+5x+14=0 are x=1,x=-2/3 ,x=7

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3 x^{3} - 22 x^{2} + 5 x + 14 = 0

x = 1, x = - \frac{2}{3}, x = 7

Decimal Notation

x = 1, x = - 0.66666 \dots, x = 7

Solution steps

3 x^{3} - 22 x^{2} + 5 x + 14 = 0

Factor

3 x^{3} - 22 x^{2} + 5 x + 14 : (x - 1) (3 x + 2) (x - 7)

(x - 1) (3 x + 2) (x - 7) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x - 1 = 0 or 3 x + 2 = 0 or x - 7 = 0

Solve

x - 1 = 0 : x = 1

Solve

3 x + 2 = 0 : x = - \frac{2}{3}

Solve

x - 7 = 0 : x = 7

The solutions are

x = 1, x = - \frac{2}{3}, x = 7

4 x^{3} - 8 x^{2} + 4 x = 0

x^{3} - x^{2} = 0

a^{6} = 30

2 x^{4} - 6 x^{3} + 8 x = 0

x, z = (2 x + 3 y)^{10}

What are the solutions to the equation 3x^3-22x^2+5x+14=0 ?
The solutions to the equation 3x^3-22x^2+5x+14=0 are x=1,x=-2/3 ,x=7
Find the zeros of 3x^3-22x^2+5x+14=0
The zeros of 3x^3-22x^2+5x+14=0 are x=1,x=-2/3 ,x=7