What are the solutions to the equation 2x^4-6x^3+8x=0 ?

The solutions to the equation 2x^4-6x^3+8x=0 are x=0,x=-1,x=2

Find the zeros of 2x^4-6x^3+8x=0

The zeros of 2x^4-6x^3+8x=0 are x=0,x=-1,x=2

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2 x^{4} - 6 x^{3} + 8 x = 0

x = 0, x = - 1, x = 2

Solution steps

2 x^{4} - 6 x^{3} + 8 x = 0

Factor

2 x^{4} - 6 x^{3} + 8 x : 2 x (x + 1) (x - 2)^{2}

2 x (x + 1) (x - 2)^{2} = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x = 0 or x + 1 = 0 or x - 2 = 0

Solve

x + 1 = 0 : x = - 1

Solve

x - 2 = 0 : x = 2

The solutions are

x = 0, x = - 1, x = 2

x, z = (2 x + 3 y)^{10}

x^{3} + 3 x^{2} - 6 x - 8

x^{3} + 3.2 x^{2} + 4.81 x = 0

n^{3} = \frac{8}{64}

24 x^{3} - 24 x^{2} - 48 x = 0

What are the solutions to the equation 2x^4-6x^3+8x=0 ?
The solutions to the equation 2x^4-6x^3+8x=0 are x=0,x=-1,x=2
Find the zeros of 2x^4-6x^3+8x=0
The zeros of 2x^4-6x^3+8x=0 are x=0,x=-1,x=2