What are the solutions to the equation roots x^3+3x^2-6x-8 ?

The solutions to the equation roots x^3+3x^2-6x-8 are x=-1,x=2,x=-4

Find the zeros of roots x^3+3x^2-6x-8

The zeros of roots x^3+3x^2-6x-8 are x=-1,x=2,x=-4

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roots

x^{3} + 3 x^{2} - 6 x - 8

x = - 1, x = 2, x = - 4

Solution steps

x^{3} + 3 x^{2} - 6 x - 8

The roots are the intercepts with the x-axis

(y = 0)

x^{3} + 3 x^{2} - 6 x - 8 = 0

Factor

x^{3} + 3 x^{2} - 6 x - 8 : (x + 1) (x - 2) (x + 4)

(x + 1) (x - 2) (x + 4) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x + 1 = 0 or x - 2 = 0 or x + 4 = 0

Solve

x + 1 = 0 : x = - 1

Solve

x - 2 = 0 : x = 2

Solve

x + 4 = 0 : x = - 4

The solutions are

x = - 1, x = 2, x = - 4

x^{3} + 3.2 x^{2} + 4.81 x = 0

n^{3} = \frac{8}{64}

24 x^{3} - 24 x^{2} - 48 x = 0

x^{6} = 4

(2 x - 2)^{4} - 3 = 0

What are the solutions to the equation roots x^3+3x^2-6x-8 ?
The solutions to the equation roots x^3+3x^2-6x-8 are x=-1,x=2,x=-4
Find the zeros of roots x^3+3x^2-6x-8
The zeros of roots x^3+3x^2-6x-8 are x=-1,x=2,x=-4