What are the solutions to the equation (2x-2)^4-3=0 ?

The solutions to the equation (2x-2)^4-3=0 are x=(\sqrt[4]{3}+2)/2 ,x=(-\sqrt[4]{3}+2)/2

Find the zeros of (2x-2)^4-3=0

The zeros of (2x-2)^4-3=0 are x=(\sqrt[4]{3}+2)/2 ,x=(-\sqrt[4]{3}+2)/2

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(2 x - 2)^{4} - 3 = 0

Decimal Notation

x = 1.65803 \dots, x = 0.34196 \dots

Solution steps

(2 x - 2)^{4} - 3 = 0

Move

3

to the right side

(2 x - 2)^{4} = 3

For

(g (x))^{n} = f (a)

, n is even, the solutions are

Solve

The solutions are

x^{3} - 12 x + 2 = 0

- m^{4} + 3 m^{2} + 2 m = 0

2 x^{3} - 4 x^{2} + 2 x - 2 = 0

x^{3} + x^{2} - 150 = 0

x^{4} - 4 x^{2} + 1

What are the solutions to the equation (2x-2)^4-3=0 ?
The solutions to the equation (2x-2)^4-3=0 are x=(\sqrt[4]{3}+2)/2 ,x=(-\sqrt[4]{3}+2)/2
Find the zeros of (2x-2)^4-3=0
The zeros of (2x-2)^4-3=0 are x=(\sqrt[4]{3}+2)/2 ,x=(-\sqrt[4]{3}+2)/2