What are the solutions to the equation 10x^3-39x^2+29x-6=0 ?

The solutions to the equation 10x^3-39x^2+29x-6=0 are x=3,x= 2/5 ,x= 1/2

Find the zeros of 10x^3-39x^2+29x-6=0

The zeros of 10x^3-39x^2+29x-6=0 are x=3,x= 2/5 ,x= 1/2

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10 x^{3} - 39 x^{2} + 29 x - 6 = 0

x = 3, x = \frac{2}{5}, x = \frac{1}{2}

Decimal Notation

x = 3, x = 0.4, x = 0.5

Solution steps

10 x^{3} - 39 x^{2} + 29 x - 6 = 0

Factor

10 x^{3} - 39 x^{2} + 29 x - 6 : (x - 3) (5 x - 2) (2 x - 1)

(x - 3) (5 x - 2) (2 x - 1) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x - 3 = 0 or 5 x - 2 = 0 or 2 x - 1 = 0

Solve

x - 3 = 0 : x = 3

Solve

5 x - 2 = 0 : x = \frac{2}{5}

Solve

2 x - 1 = 0 : x = \frac{1}{2}

The solutions are

x = 3, x = \frac{2}{5}, x = \frac{1}{2}

4 x^{3} - 54 x^{2} + 240 x - 350 = 0

x^{3} - 64 = 0

y, 3 x^{3} + 9 x y^{2} = 5 x^{3}

y, x = 1 - y^{4}

4 x^{3} - 6 x^{2} + 2 = 0

What are the solutions to the equation 10x^3-39x^2+29x-6=0 ?
The solutions to the equation 10x^3-39x^2+29x-6=0 are x=3,x= 2/5 ,x= 1/2
Find the zeros of 10x^3-39x^2+29x-6=0
The zeros of 10x^3-39x^2+29x-6=0 are x=3,x= 2/5 ,x= 1/2