What are the solutions to the equation 4x^3-54x^2+240x-350=0 ?

The solutions to the equation 4x^3-54x^2+240x-350=0 are x=5,x= 7/2

Find the zeros of 4x^3-54x^2+240x-350=0

The zeros of 4x^3-54x^2+240x-350=0 are x=5,x= 7/2

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4 x^{3} - 54 x^{2} + 240 x - 350 = 0

x = 5, x = \frac{7}{2}

Decimal Notation

x = 5, x = 3.5

Solution steps

4 x^{3} - 54 x^{2} + 240 x - 350 = 0

Factor

4 x^{3} - 54 x^{2} + 240 x - 350 : 2 (x - 5)^{2} (2 x - 7)

2 (x - 5)^{2} (2 x - 7) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x - 5 = 0 or 2 x - 7 = 0

Solve

x - 5 = 0 : x = 5

Solve

2 x - 7 = 0 : x = \frac{7}{2}

The solutions are

x = 5, x = \frac{7}{2}

x^{3} - 64 = 0

y, 3 x^{3} + 9 x y^{2} = 5 x^{3}

y, x = 1 - y^{4}

4 x^{3} - 6 x^{2} + 2 = 0

4 z^{4} - 5 i z^{2} + 1 = 0

What are the solutions to the equation 4x^3-54x^2+240x-350=0 ?
The solutions to the equation 4x^3-54x^2+240x-350=0 are x=5,x= 7/2
Find the zeros of 4x^3-54x^2+240x-350=0
The zeros of 4x^3-54x^2+240x-350=0 are x=5,x= 7/2