What are the solutions to the equation 3x^3-25x^2+58x-40=0 ?

The solutions to the equation 3x^3-25x^2+58x-40=0 are x=2,x= 4/3 ,x=5

Find the zeros of 3x^3-25x^2+58x-40=0

The zeros of 3x^3-25x^2+58x-40=0 are x=2,x= 4/3 ,x=5

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3 x^{3} - 25 x^{2} + 58 x - 40 = 0

x = 2, x = \frac{4}{3}, x = 5

Decimal Notation

x = 2, x = 1.33333 \dots, x = 5

Solution steps

3 x^{3} - 25 x^{2} + 58 x - 40 = 0

Factor

3 x^{3} - 25 x^{2} + 58 x - 40 : (x - 2) (3 x - 4) (x - 5)

(x - 2) (3 x - 4) (x - 5) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x - 2 = 0 or 3 x - 4 = 0 or x - 5 = 0

Solve

x - 2 = 0 : x = 2

Solve

3 x - 4 = 0 : x = \frac{4}{3}

Solve

x - 5 = 0 : x = 5

The solutions are

x = 2, x = \frac{4}{3}, x = 5

x^{4} + 8 x^{3} + 8 x^{2} + 8 x + 7 = 0

x^{3} - 9 x^{2} - 4 x + 36 = 0

x^{12} - x^{6} - 30 = 0

240 x^{3} + 360 x^{2} - 1800 x = 0

x^{3} - 2 x^{2} + 9 x - 18

What are the solutions to the equation 3x^3-25x^2+58x-40=0 ?
The solutions to the equation 3x^3-25x^2+58x-40=0 are x=2,x= 4/3 ,x=5
Find the zeros of 3x^3-25x^2+58x-40=0
The zeros of 3x^3-25x^2+58x-40=0 are x=2,x= 4/3 ,x=5