What are the solutions to the equation x^4-4x^3+16x-16=0 ?

The solutions to the equation x^4-4x^3+16x-16=0 are x=-2,x=2

Find the zeros of x^4-4x^3+16x-16=0

The zeros of x^4-4x^3+16x-16=0 are x=-2,x=2

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x^{4} - 4 x^{3} + 16 x - 16 = 0

x = - 2, x = 2

Solution steps

x^{4} - 4 x^{3} + 16 x - 16 = 0

Factor

x^{4} - 4 x^{3} + 16 x - 16 : (x + 2) (x - 2)^{3}

(x + 2) (x - 2)^{3} = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x + 2 = 0 or x - 2 = 0

Solve

x + 2 = 0 : x = - 2

Solve

x - 2 = 0 : x = 2

The solutions are

x = - 2, x = 2

x^{4} - 3 x^{2} + 2 x = 0

x^{3} - 7 x^{2} + 5 x + 25 = 0

x^{3} + 5 x^{2} + 4 x + 20

x, x^{3} = a t^{2}

12 x^{3} - 20 x^{2} + x + 3

What are the solutions to the equation x^4-4x^3+16x-16=0 ?
The solutions to the equation x^4-4x^3+16x-16=0 are x=-2,x=2
Find the zeros of x^4-4x^3+16x-16=0
The zeros of x^4-4x^3+16x-16=0 are x=-2,x=2