What are the solutions to the equation x^3-7x^2+5x+25=0 ?

The solutions to the equation x^3-7x^2+5x+25=0 are x=5,x=1+sqrt(6),x=1-sqrt(6)

Find the zeros of x^3-7x^2+5x+25=0

The zeros of x^3-7x^2+5x+25=0 are x=5,x=1+sqrt(6),x=1-sqrt(6)

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x^{3} - 7 x^{2} + 5 x + 25 = 0

x = 5, x = 1 + 6, x = 1 - 6

Decimal Notation

x = 5, x = 3.44948 \dots, x = - 1.44948 \dots

Solution steps

x^{3} - 7 x^{2} + 5 x + 25 = 0

Factor

x^{3} - 7 x^{2} + 5 x + 25 : (x - 5) (x^{2} - 2 x - 5)

(x - 5) (x^{2} - 2 x - 5) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x - 5 = 0 or x^{2} - 2 x - 5 = 0

Solve

x - 5 = 0 : x = 5

Solve

x^{2} - 2 x - 5 = 0 : x = 1 + 6, x = 1 - 6

The solutions are

x = 5, x = 1 + 6, x = 1 - 6

x^{3} + 5 x^{2} + 4 x + 20

x, x^{3} = a t^{2}

12 x^{3} - 20 x^{2} + x + 3

3 x^{4} + 5 x^{3} - 12 x^{2} - 20 x = 0

5 x^{3} + 29 x^{2} + 19 x - 5 = 0

What are the solutions to the equation x^3-7x^2+5x+25=0 ?
The solutions to the equation x^3-7x^2+5x+25=0 are x=5,x=1+sqrt(6),x=1-sqrt(6)
Find the zeros of x^3-7x^2+5x+25=0
The zeros of x^3-7x^2+5x+25=0 are x=5,x=1+sqrt(6),x=1-sqrt(6)