What are the solutions to the equation x^4-9x^3+27x^2-27x=0 ?

The solutions to the equation x^4-9x^3+27x^2-27x=0 are x=0,x=3

Find the zeros of x^4-9x^3+27x^2-27x=0

The zeros of x^4-9x^3+27x^2-27x=0 are x=0,x=3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

x^{4} - 9 x^{3} + 27 x^{2} - 27 x = 0

x = 0, x = 3

Solution steps

x^{4} - 9 x^{3} + 27 x^{2} - 27 x = 0

Factor

x^{4} - 9 x^{3} + 27 x^{2} - 27 x : x (x - 3)^{3}

x (x - 3)^{3} = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x = 0 or x - 3 = 0

Solve

x - 3 = 0 : x = 3

The solutions are

x = 0, x = 3

x^{5} - 3 \cdot x^{2} + x + 1 = 0

x^{3} + 3 x^{2} - 18 x - 40 = 0

y, 25 x^{4} - 625 y - 500 = 0

x^{4} + 2 x^{2} - x + 8

101 x^{100} + 51 x^{50} + 1 = 0

What are the solutions to the equation x^4-9x^3+27x^2-27x=0 ?
The solutions to the equation x^4-9x^3+27x^2-27x=0 are x=0,x=3
Find the zeros of x^4-9x^3+27x^2-27x=0
The zeros of x^4-9x^3+27x^2-27x=0 are x=0,x=3