What are the solutions to the equation 5x^3-x^2-5x+1=0 ?

The solutions to the equation 5x^3-x^2-5x+1=0 are x= 1/5 ,x=-1,x=1

Find the zeros of 5x^3-x^2-5x+1=0

The zeros of 5x^3-x^2-5x+1=0 are x= 1/5 ,x=-1,x=1

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5 x^{3} - x^{2} - 5 x + 1 = 0

x = \frac{1}{5}, x = - 1, x = 1

Decimal Notation

x = 0.2, x = - 1, x = 1

Solution steps

5 x^{3} - x^{2} - 5 x + 1 = 0

Factor

5 x^{3} - x^{2} - 5 x + 1 : (5 x - 1) (x + 1) (x - 1)

(5 x - 1) (x + 1) (x - 1) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

5 x - 1 = 0 or x + 1 = 0 or x - 1 = 0

Solve

5 x - 1 = 0 : x = \frac{1}{5}

Solve

x + 1 = 0 : x = - 1

Solve

x - 1 = 0 : x = 1

The solutions are

x = \frac{1}{5}, x = - 1, x = 1

2 x^{3} - 5 x^{2} + x + 2

y^{4} - 4 = 0

z^{6} + 6 z^{3} + 10 = 0

- 2 x^{4} + x^{3} - x^{2} + 4 x

- 3 x^{3} + 5 x^{2} - 27 x + 45 = 0

What are the solutions to the equation 5x^3-x^2-5x+1=0 ?
The solutions to the equation 5x^3-x^2-5x+1=0 are x= 1/5 ,x=-1,x=1
Find the zeros of 5x^3-x^2-5x+1=0
The zeros of 5x^3-x^2-5x+1=0 are x= 1/5 ,x=-1,x=1