What are the solutions to the equation -3x^3+5x^2-27x+45=0 ?

The solutions to the equation -3x^3+5x^2-27x+45=0 are x= 5/3 ,x=3i,x=-3i

Find the zeros of -3x^3+5x^2-27x+45=0

The zeros of -3x^3+5x^2-27x+45=0 are x= 5/3 ,x=3i,x=-3i

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

- 3 x^{3} + 5 x^{2} - 27 x + 45 = 0

x = \frac{5}{3}, x = 3 i, x = - 3 i

Solution steps

- 3 x^{3} + 5 x^{2} - 27 x + 45 = 0

Factor

- 3 x^{3} + 5 x^{2} - 27 x + 45 : - (3 x - 5) (x^{2} + 9)

- (3 x - 5) (x^{2} + 9) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

3 x - 5 = 0 or x^{2} + 9 = 0

Solve

3 x - 5 = 0 : x = \frac{5}{3}

Solve

x^{2} + 9 = 0 : x = 3 i, x = - 3 i

The solutions are

x = \frac{5}{3}, x = 3 i, x = - 3 i

2 x^{4} - 9 x^{3} + 17 x^{2} - 36 x + 36 = 0

x^{4} + 7 x^{3} + 8 x^{2} - 7 x + 15 = 0

x^{3} + 2 x = 3 x^{2}

x^{3} + 5 x^{2} - 13 x + 7 = 0

x^{3} + 5 x^{2} + 24 x + 20 = 0

What are the solutions to the equation -3x^3+5x^2-27x+45=0 ?
The solutions to the equation -3x^3+5x^2-27x+45=0 are x= 5/3 ,x=3i,x=-3i
Find the zeros of -3x^3+5x^2-27x+45=0
The zeros of -3x^3+5x^2-27x+45=0 are x= 5/3 ,x=3i,x=-3i