What are the solutions to the equation (x^2-2x)(4-x)=0 ?

The solutions to the equation (x^2-2x)(4-x)=0 are x=0,x=2,x=4

Find the zeros of (x^2-2x)(4-x)=0

The zeros of (x^2-2x)(4-x)=0 are x=0,x=2,x=4

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(x^{2} - 2 x) (4 - x) = 0

x = 0, x = 2, x = 4

Solution steps

(x^{2} - 2 x) (4 - x) = 0

Factor

(x^{2} - 2 x) (4 - x) : - x (x - 2) (x - 4)

- x (x - 2) (x - 4) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x = 0 or x - 2 = 0 or x - 4 = 0

Solve

x - 2 = 0 : x = 2

Solve

x - 4 = 0 : x = 4

The solutions are

x = 0, x = 2, x = 4

x^{4} - x^{3} - 27 x + 27

6 x^{4} + 8 x^{3} = 0

2 x^{3} - 5 x^{2} + 8 x - 5

x^{2} 3 x + 2 = 0

x^{4} + 6 x^{3} + 15 x^{2} + 20 x + 12

What are the solutions to the equation (x^2-2x)(4-x)=0 ?
The solutions to the equation (x^2-2x)(4-x)=0 are x=0,x=2,x=4
Find the zeros of (x^2-2x)(4-x)=0
The zeros of (x^2-2x)(4-x)=0 are x=0,x=2,x=4