What are the solutions to the equation z^3=(-sqrt(3)+i) ?

The solutions to the equation z^3=(-sqrt(3)+i) are

Find the zeros of z^3=(-sqrt(3)+i)

The zeros of z^3=(-sqrt(3)+i) are

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z^{3} = (- 3 + i)

Solution steps

z^{3} = (- 3 + i)

Remove parentheses:

(a) = a

z^{3} = - 3 + i

For

z^{n} = a

the solutions are

k = 0, 1, \dots, n - 1

For

n = 3, a = - 3 + i

∣ a ∣ = 2

ar g (a) = - \frac{π}{6} + π

Simplify

2 x^{3} + 2 x^{2} - 19 x + 20 = 0

3 x^{3} + 7 x^{2} - 4 = 0

y, x = y^{3} - 1

4 x^{3} + 12 x^{2} - 36 x = 0

x^{5} + x^{15} + x^{25} = 780

What are the solutions to the equation z^3=(-sqrt(3)+i) ?
The solutions to the equation z^3=(-sqrt(3)+i) are
Find the zeros of z^3=(-sqrt(3)+i)
The zeros of z^3=(-sqrt(3)+i) are