What are the solutions to the equation 2x^2+8x=0 ?

The solutions to the equation 2x^2+8x=0 are x=0,x=-4

Find the zeros of 2x^2+8x=0

The zeros of 2x^2+8x=0 are x=0,x=-4

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2 x^{2} + 8 x = 0

x = 0, x = - 4

Solution steps

2 x^{2} + 8 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 \cdot 2 \cdot 0}{2 \cdot 2}

8^{2} - 4 \cdot 2 \cdot 0 = 8

x_{1, 2} = \frac{- 8 \pm 8}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- 8 + 8}{2 \cdot 2}, x_{2} = \frac{- 8 - 8}{2 \cdot 2}

x = \frac{- 8 + 8}{2 \cdot 2} : 0

x = \frac{- 8 - 8}{2 \cdot 2} : - 4

The solutions to the quadratic equation are:

x = 0, x = - 4

- \frac{1}{2} - 2

x^{2} - 5 x + x - 5

x^{2} + 11 x + 24 = 0

\frac{- 48 c ^{2} d ^{4}}{- 8 c d}

\frac{2 x}{9} + \frac{1}{3} = \frac{4}{15}

What are the solutions to the equation 2x^2+8x=0 ?
The solutions to the equation 2x^2+8x=0 are x=0,x=-4
Find the zeros of 2x^2+8x=0
The zeros of 2x^2+8x=0 are x=0,x=-4