What are the solutions to the equation 2x^3+6x=0 ?

The solutions to the equation 2x^3+6x=0 are x=0,x=sqrt(3)i,x=-sqrt(3)i

Find the zeros of 2x^3+6x=0

The zeros of 2x^3+6x=0 are x=0,x=sqrt(3)i,x=-sqrt(3)i

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2 x^{3} + 6 x = 0

x = 0, x = 3 i, x = - 3 i

Solution steps

2 x^{3} + 6 x = 0

Factor

2 x^{3} + 6 x : 2 x (x^{2} + 3)

2 x (x^{2} + 3) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x = 0 or x^{2} + 3 = 0

Solve

x^{2} + 3 = 0 : x = 3 i, x = - 3 i

The solutions are

x = 0, x = 3 i, x = - 3 i

x^{4} - 6 x^{3} - 3 x^{2} + 24 x - 4 = 0

x^{6} + 4 x^{3} + 8 = 0

x^{5} = x^{4}

x^{3} + 3 x^{2} - 4 x - 12 = 0

D, 2 b - hb = D^{3}

What are the solutions to the equation 2x^3+6x=0 ?
The solutions to the equation 2x^3+6x=0 are x=0,x=sqrt(3)i,x=-sqrt(3)i
Find the zeros of 2x^3+6x=0
The zeros of 2x^3+6x=0 are x=0,x=sqrt(3)i,x=-sqrt(3)i