What are the solutions to the equation x^3-3x^2-7x+21=0 ?

The solutions to the equation x^3-3x^2-7x+21=0 are x=3,x=-sqrt(7),x=sqrt(7)

Find the zeros of x^3-3x^2-7x+21=0

The zeros of x^3-3x^2-7x+21=0 are x=3,x=-sqrt(7),x=sqrt(7)

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x^{3} - 3 x^{2} - 7 x + 21 = 0

x = 3, x = - 7, x = 7

Decimal Notation

x = 3, x = - 2.64575 \dots, x = 2.64575 \dots

Solution steps

x^{3} - 3 x^{2} - 7 x + 21 = 0

Factor

x^{3} - 3 x^{2} - 7 x + 21 : (x - 3) (x + 7) (x - 7)

(x - 3) (x + 7) (x - 7) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x - 3 = 0 or x + 7 = 0 or x - 7 = 0

Solve

x - 3 = 0 : x = 3

Solve

x + 7 = 0 : x = - 7

Solve

x - 7 = 0 : x = 7

The solutions are

x = 3, x = - 7, x = 7

(9 x - 3)^{4} - 2 = 0

x = c x (x - 1)^{2}

0 = 2 x^{3} + 3 x^{2} - 18 x - 27

x^{3} - 3 x^{2} + 7 x - 5 = 0

x^{4} - 65 x^{2} + 64 = 0

What are the solutions to the equation x^3-3x^2-7x+21=0 ?
The solutions to the equation x^3-3x^2-7x+21=0 are x=3,x=-sqrt(7),x=sqrt(7)
Find the zeros of x^3-3x^2-7x+21=0
The zeros of x^3-3x^2-7x+21=0 are x=3,x=-sqrt(7),x=sqrt(7)