What are the solutions to the equation x^3+3x^2+12x+4=0 ?

The solutions to the equation x^3+3x^2+12x+4=0 are x\approx-0.36216…

Find the zeros of x^3+3x^2+12x+4=0

The zeros of x^3+3x^2+12x+4=0 are x\approx-0.36216…

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x^{3} + 3 x^{2} + 12 x + 4 = 0

x \approx - 0.36216 \dots

Solution steps

x^{3} + 3 x^{2} + 12 x + 4 = 0

Find one solution for

x^{3} + 3 x^{2} + 12 x + 4 = 0

using Newton-Raphson:

x \approx - 0.36216 \dots

Apply long division:

\frac{x ^{3} + 3 x ^{2} + 12 x + 4}{x + 0.36216 \dots} = x^{2} + 2.63783 \dots x + 11.04466 \dots

x^{2} + 2.63783 \dots x + 11.04466 \dots \approx 0

Find one solution for

x^{2} + 2.63783 \dots x + 11.04466 \dots = 0

using Newton-Raphson:

No Solution for

x \in R

The solution is

x \approx - 0.36216 \dots

x^{5} + x^{4} + x^{3} + x^{2} + x + 1

- 3 x^{3} - 4 x^{2} + 5 x + 2 = 0

4 x^{4} - 39 x^{3} + 54 x^{2} + 16 x

(x^{2} + 1) (4 + x) = 0

x^{3} - 2 x^{2} - 9 = 0

What are the solutions to the equation x^3+3x^2+12x+4=0 ?
The solutions to the equation x^3+3x^2+12x+4=0 are x\approx-0.36216…
Find the zeros of x^3+3x^2+12x+4=0
The zeros of x^3+3x^2+12x+4=0 are x\approx-0.36216…