What are the solutions to the equation roots 4x^4-39x^3+54x^2+16x ?

The solutions to the equation roots 4x^4-39x^3+54x^2+16x are x=0,x=2,x=-1/4 ,x=8

Find the zeros of roots 4x^4-39x^3+54x^2+16x

The zeros of roots 4x^4-39x^3+54x^2+16x are x=0,x=2,x=-1/4 ,x=8

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roots

4 x^{4} - 39 x^{3} + 54 x^{2} + 16 x

x = 0, x = 2, x = - \frac{1}{4}, x = 8

Solution steps

4 x^{4} - 39 x^{3} + 54 x^{2} + 16 x

The roots are the intercepts with the x-axis

(y = 0)

4 x^{4} - 39 x^{3} + 54 x^{2} + 16 x = 0

Factor

4 x^{4} - 39 x^{3} + 54 x^{2} + 16 x : x (x - 2) (4 x + 1) (x - 8)

x (x - 2) (4 x + 1) (x - 8) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x = 0 or x - 2 = 0 or 4 x + 1 = 0 or x - 8 = 0

Solve

x - 2 = 0 : x = 2

Solve

4 x + 1 = 0 : x = - \frac{1}{4}

Solve

x - 8 = 0 : x = 8

The solutions are

x = 0, x = 2, x = - \frac{1}{4}, x = 8

(x^{2} + 1) (4 + x) = 0

x^{3} - 2 x^{2} - 9 = 0

x^{3} + 125

x^{3} = - 8 i

2 x^{3} - 10 x^{2} - 72 x = 0

What are the solutions to the equation roots 4x^4-39x^3+54x^2+16x ?
The solutions to the equation roots 4x^4-39x^3+54x^2+16x are x=0,x=2,x=-1/4 ,x=8
Find the zeros of roots 4x^4-39x^3+54x^2+16x
The zeros of roots 4x^4-39x^3+54x^2+16x are x=0,x=2,x=-1/4 ,x=8