What are the solutions to the equation z^3+125=0 ?

The solutions to the equation z^3+125=0 are z=-5,z= 5/2-(5sqrt(3))/2 i,z= 5/2+(5sqrt(3))/2 i

Find the zeros of z^3+125=0

The zeros of z^3+125=0 are z=-5,z= 5/2-(5sqrt(3))/2 i,z= 5/2+(5sqrt(3))/2 i

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z^{3} + 125 = 0

z = - 5, z = \frac{5}{2} - \frac{5 3}{2} i, z = \frac{5}{2} + \frac{5 3}{2} i

Solution steps

z^{3} + 125 = 0

Move

125

to the right side

z^{3} = - 125

For

x^{3} = f (a)

the solutions are

Simplify

z = - 5, z = \frac{5}{2} - \frac{5 3}{2} i, z = \frac{5}{2} + \frac{5 3}{2} i

x^{4} - x - 2 = 0

- \frac{3}{4} x^{5} = 96

x^{3} + x = 0

y, x^{3} - y^{3} = 0

- x^{3} + 5 x^{2} + x - 5 = 0

What are the solutions to the equation z^3+125=0 ?
The solutions to the equation z^3+125=0 are z=-5,z= 5/2-(5sqrt(3))/2 i,z= 5/2+(5sqrt(3))/2 i
Find the zeros of z^3+125=0
The zeros of z^3+125=0 are z=-5,z= 5/2-(5sqrt(3))/2 i,z= 5/2+(5sqrt(3))/2 i