What are the solutions to the equation 3x^3-3x^2-7x+5=x^3-2x^2-1 ?

The solutions to the equation 3x^3-3x^2-7x+5=x^3-2x^2-1 are x=1,x= 3/2 ,x=-2

Find the zeros of 3x^3-3x^2-7x+5=x^3-2x^2-1

The zeros of 3x^3-3x^2-7x+5=x^3-2x^2-1 are x=1,x= 3/2 ,x=-2

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3 x^{3} - 3 x^{2} - 7 x + 5 = x^{3} - 2 x^{2} - 1

x = 1, x = \frac{3}{2}, x = - 2

Decimal Notation

x = 1, x = 1.5, x = - 2

Solution steps

3 x^{3} - 3 x^{2} - 7 x + 5 = x^{3} - 2 x^{2} - 1

Move

1

to the left side

3 x^{3} - 3 x^{2} - 7 x + 6 = x^{3} - 2 x^{2}

Move

2 x^{2}

to the left side

3 x^{3} - x^{2} - 7 x + 6 = x^{3}

Move

x^{3}

to the left side

2 x^{3} - x^{2} - 7 x + 6 = 0

Factor

2 x^{3} - x^{2} - 7 x + 6 : (x - 1) (2 x - 3) (x + 2)

(x - 1) (2 x - 3) (x + 2) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x - 1 = 0 or 2 x - 3 = 0 or x + 2 = 0

Solve

x - 1 = 0 : x = 1

Solve

2 x - 3 = 0 : x = \frac{3}{2}

Solve

x + 2 = 0 : x = - 2

The solutions are

x = 1, x = \frac{3}{2}, x = - 2

4 x^{3} - 6 x + 2 = 0

12 x^{2} + 48 x = - x^{3} - 64

0.75 = 10 x^{9} - 9 x^{10}

x^{4} - 2 x^{2} + 6 = 0

4 x^{3} - 9 x^{2} + 4 = 0

What are the solutions to the equation 3x^3-3x^2-7x+5=x^3-2x^2-1 ?
The solutions to the equation 3x^3-3x^2-7x+5=x^3-2x^2-1 are x=1,x= 3/2 ,x=-2
Find the zeros of 3x^3-3x^2-7x+5=x^3-2x^2-1
The zeros of 3x^3-3x^2-7x+5=x^3-2x^2-1 are x=1,x= 3/2 ,x=-2