What are the solutions to the equation x^3-13x^2-x+13=0 ?

The solutions to the equation x^3-13x^2-x+13=0 are x=13,x=-1,x=1

Find the zeros of x^3-13x^2-x+13=0

The zeros of x^3-13x^2-x+13=0 are x=13,x=-1,x=1

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x^{3} - 13 x^{2} - x + 13 = 0

x = 13, x = - 1, x = 1

Solution steps

x^{3} - 13 x^{2} - x + 13 = 0

Factor

x^{3} - 13 x^{2} - x + 13 : (x - 13) (x + 1) (x - 1)

(x - 13) (x + 1) (x - 1) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x - 13 = 0 or x + 1 = 0 or x - 1 = 0

Solve

x - 13 = 0 : x = 13

Solve

x + 1 = 0 : x = - 1

Solve

x - 1 = 0 : x = 1

The solutions are

x = 13, x = - 1, x = 1

y, (4 x + 5 y)^{6} = x

x^{4} + 7 x^{2} + 18 x + 10 = 0

x^{5} - 36 x = 0

x^{3} - 3 x^{2} + 2 x = 0

(1 + x)^{3} = 1.08056955

What are the solutions to the equation x^3-13x^2-x+13=0 ?
The solutions to the equation x^3-13x^2-x+13=0 are x=13,x=-1,x=1
Find the zeros of x^3-13x^2-x+13=0
The zeros of x^3-13x^2-x+13=0 are x=13,x=-1,x=1