What are the solutions to the equation 2x^4+3x^3+16x+24=0 ?

The solutions to the equation 2x^4+3x^3+16x+24=0 are x=-2,x=-3/2 ,x=1+sqrt(3)i,x=1-sqrt(3)i

Find the zeros of 2x^4+3x^3+16x+24=0

The zeros of 2x^4+3x^3+16x+24=0 are x=-2,x=-3/2 ,x=1+sqrt(3)i,x=1-sqrt(3)i

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2 x^{4} + 3 x^{3} + 16 x + 24 = 0

x = - 2, x = - \frac{3}{2}, x = 1 + 3 i, x = 1 - 3 i

Solution steps

2 x^{4} + 3 x^{3} + 16 x + 24 = 0

Factor

2 x^{4} + 3 x^{3} + 16 x + 24 : (x + 2) (2 x + 3) (x^{2} - 2 x + 4)

(x + 2) (2 x + 3) (x^{2} - 2 x + 4) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x + 2 = 0 or 2 x + 3 = 0 or x^{2} - 2 x + 4 = 0

Solve

x + 2 = 0 : x = - 2

Solve

2 x + 3 = 0 : x = - \frac{3}{2}

Solve

x^{2} - 2 x + 4 = 0 : x = 1 + 3 i, x = 1 - 3 i

The solutions are

x = - 2, x = - \frac{3}{2}, x = 1 + 3 i, x = 1 - 3 i

x^{4} - (x - 0.005)^{4} - 0. 1^{4} = 0

x^{3} + 3 x^{2} + 9 x + 27

4 x^{3} - 8 x + 1 = 0

2 m x^{4} + 3 n x^{4} + 10 m + 15 n

A, A^{4} t = m - R^{2}

What are the solutions to the equation 2x^4+3x^3+16x+24=0 ?
The solutions to the equation 2x^4+3x^3+16x+24=0 are x=-2,x=-3/2 ,x=1+sqrt(3)i,x=1-sqrt(3)i
Find the zeros of 2x^4+3x^3+16x+24=0
The zeros of 2x^4+3x^3+16x+24=0 are x=-2,x=-3/2 ,x=1+sqrt(3)i,x=1-sqrt(3)i