What are the solutions to the equation x^3-5x^2-7x+51=0 ?

The solutions to the equation x^3-5x^2-7x+51=0 are x=-3,x=4+i,x=4-i

Find the zeros of x^3-5x^2-7x+51=0

The zeros of x^3-5x^2-7x+51=0 are x=-3,x=4+i,x=4-i

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

x^{3} - 5 x^{2} - 7 x + 51 = 0

x = - 3, x = 4 + i, x = 4 - i

Solution steps

x^{3} - 5 x^{2} - 7 x + 51 = 0

Factor

x^{3} - 5 x^{2} - 7 x + 51 : (x + 3) (x^{2} - 8 x + 17)

(x + 3) (x^{2} - 8 x + 17) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x + 3 = 0 or x^{2} - 8 x + 17 = 0

Solve

x + 3 = 0 : x = - 3

Solve

x^{2} - 8 x + 17 = 0 : x = 4 + i, x = 4 - i

The solutions are

x = - 3, x = 4 + i, x = 4 - i

x^{5} = i

r^{5} + 5 r^{4} - 2 r^{3} - 10 r^{2} + r + 5 = 0

x^{3} - 3 x^{2} + 7 x - 5

\frac{1}{3} x^{3} + x^{2} + 1 = 0

(x - 1)^{2} (x - 2) = 0

What are the solutions to the equation x^3-5x^2-7x+51=0 ?
The solutions to the equation x^3-5x^2-7x+51=0 are x=-3,x=4+i,x=4-i
Find the zeros of x^3-5x^2-7x+51=0
The zeros of x^3-5x^2-7x+51=0 are x=-3,x=4+i,x=4-i