What are the solutions to the equation roots s^3+s^2+1 ?

The solutions to the equation roots s^3+s^2+1 are s\approx-1.46557…

Find the zeros of roots s^3+s^2+1

The zeros of roots s^3+s^2+1 are s\approx-1.46557…

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roots

s^{3} + s^{2} + 1

s \approx - 1.46557 \dots

Solution steps

s^{3} + s^{2} + 1

The roots are the intercepts with the x-axis

(y = 0)

s^{3} + s^{2} + 1 = 0

Find one solution for

s^{3} + s^{2} + 1 = 0

using Newton-Raphson:

s \approx - 1.46557 \dots

Apply long division:

\frac{s ^{3} + s ^{2} + 1}{s + 1.46557 \dots} = s^{2} - 0.46557 \dots s + 0.68232 \dots

s^{2} - 0.46557 \dots s + 0.68232 \dots \approx 0

Find one solution for

s^{2} - 0.46557 \dots s + 0.68232 \dots = 0

using Newton-Raphson:

No Solution for

s \in R

The solution is

s \approx - 1.46557 \dots

m (m - 1) (m - 2) - 6 = 0

7 x^{6} = - 15

x^{4} - 4 x^{3} + 2 x^{2} + 4 x + 3 = 0

3 x^{3} + 18 x^{2} + 10 x = - 5 x

x^{3} - 6 x^{2} - 36 x + 216 = 0

What are the solutions to the equation roots s^3+s^2+1 ?
The solutions to the equation roots s^3+s^2+1 are s\approx-1.46557…
Find the zeros of roots s^3+s^2+1
The zeros of roots s^3+s^2+1 are s\approx-1.46557…