What are the solutions to the equation x^4-4x^3+2x^2+4x+3=0 ?

The solutions to the equation x^4-4x^3+2x^2+4x+3=0 are No Solution for x\in\mathbb{R}

Find the zeros of x^4-4x^3+2x^2+4x+3=0

The zeros of x^4-4x^3+2x^2+4x+3=0 are No Solution for x\in\mathbb{R}

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x^{4} - 4 x^{3} + 2 x^{2} + 4 x + 3 = 0

No Solution for x \in R

Solution steps

x^{4} - 4 x^{3} + 2 x^{2} + 4 x + 3 = 0

Find one solution for

x^{4} - 4 x^{3} + 2 x^{2} + 4 x + 3 = 0

using Newton-Raphson:

No Solution for

x \in R

The solution is

No Solution for x \in R

3 x^{3} + 18 x^{2} + 10 x = - 5 x

x^{3} - 6 x^{2} - 36 x + 216 = 0

n^{3} - n = 8 n^{2} - 8

x^{3} - 5 x^{2} + x + 15 = 0

4 x^{3} + 3 x^{2} - 40 x + 1 = 0

What are the solutions to the equation x^4-4x^3+2x^2+4x+3=0 ?
The solutions to the equation x^4-4x^3+2x^2+4x+3=0 are No Solution for x\in\mathbb{R}
Find the zeros of x^4-4x^3+2x^2+4x+3=0
The zeros of x^4-4x^3+2x^2+4x+3=0 are No Solution for x\in\mathbb{R}