What are the solutions to the equation x^3-5x^2+x+15=0 ?

The solutions to the equation x^3-5x^2+x+15=0 are x=3,x=1+sqrt(6),x=1-sqrt(6)

Find the zeros of x^3-5x^2+x+15=0

The zeros of x^3-5x^2+x+15=0 are x=3,x=1+sqrt(6),x=1-sqrt(6)

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x^{3} - 5 x^{2} + x + 15 = 0

x = 3, x = 1 + 6, x = 1 - 6

Decimal Notation

x = 3, x = 3.44948 \dots, x = - 1.44948 \dots

Solution steps

x^{3} - 5 x^{2} + x + 15 = 0

Factor

x^{3} - 5 x^{2} + x + 15 : (x - 3) (x^{2} - 2 x - 5)

(x - 3) (x^{2} - 2 x - 5) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x - 3 = 0 or x^{2} - 2 x - 5 = 0

Solve

x - 3 = 0 : x = 3

Solve

x^{2} - 2 x - 5 = 0 : x = 1 + 6, x = 1 - 6

The solutions are

x = 3, x = 1 + 6, x = 1 - 6

4 x^{3} + 3 x^{2} - 40 x + 1 = 0

2 x^{4} + x^{3} - 24 x^{2} + 20 x + 16 = 0

2 x^{4} - 5 x^{2} - 3 = 0

5 x^{4} + 3 x^{2} + x^{2} - x = 0

x^{3} - 3 x = - 2

What are the solutions to the equation x^3-5x^2+x+15=0 ?
The solutions to the equation x^3-5x^2+x+15=0 are x=3,x=1+sqrt(6),x=1-sqrt(6)
Find the zeros of x^3-5x^2+x+15=0
The zeros of x^3-5x^2+x+15=0 are x=3,x=1+sqrt(6),x=1-sqrt(6)