What are the solutions to the equation 3x^4+4x^3+6x-4=0 ?

The solutions to the equation 3x^4+4x^3+6x-4=0 are x=-2,x\approx 0.52890…

Find the zeros of 3x^4+4x^3+6x-4=0

The zeros of 3x^4+4x^3+6x-4=0 are x=-2,x\approx 0.52890…

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3 x^{4} + 4 x^{3} + 6 x - 4 = 0

x = - 2, x \approx 0.52890 \dots

Solution steps

3 x^{4} + 4 x^{3} + 6 x - 4 = 0

Factor

3 x^{4} + 4 x^{3} + 6 x - 4 : (x + 2) (3 x^{3} - 2 x^{2} + 4 x - 2)

(x + 2) (3 x^{3} - 2 x^{2} + 4 x - 2) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x + 2 = 0 or 3 x^{3} - 2 x^{2} + 4 x - 2 = 0

Solve

x + 2 = 0 : x = - 2

Solve

3 x^{3} - 2 x^{2} + 4 x - 2 = 0 : x \approx 0.52890 \dots

The solutions are

x = - 2, x \approx 0.52890 \dots

n^{3} - 9 n^{2} - n + 9 = 0

y, 4 x^{3} - 16 y = 4 y^{3} - 16 x

4 x^{7} - 64 x^{3} = 0

N, b a^{2} + 3 = N^{3}

(x - 1)^{4} - 2 (x - 1)^{2} - 3 = 0

What are the solutions to the equation 3x^4+4x^3+6x-4=0 ?
The solutions to the equation 3x^4+4x^3+6x-4=0 are x=-2,x\approx 0.52890…
Find the zeros of 3x^4+4x^3+6x-4=0
The zeros of 3x^4+4x^3+6x-4=0 are x=-2,x\approx 0.52890…