What are the solutions to the equation 2x^3-x^2-22x-24=0 ?

The solutions to the equation 2x^3-x^2-22x-24=0 are x=-2,x=-3/2 ,x=4

Find the zeros of 2x^3-x^2-22x-24=0

The zeros of 2x^3-x^2-22x-24=0 are x=-2,x=-3/2 ,x=4

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2 x^{3} - x^{2} - 22 x - 24 = 0

x = - 2, x = - \frac{3}{2}, x = 4

Decimal Notation

x = - 2, x = - 1.5, x = 4

Solution steps

2 x^{3} - x^{2} - 22 x - 24 = 0

Factor

2 x^{3} - x^{2} - 22 x - 24 : (x + 2) (2 x + 3) (x - 4)

(x + 2) (2 x + 3) (x - 4) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x + 2 = 0 or 2 x + 3 = 0 or x - 4 = 0

Solve

x + 2 = 0 : x = - 2

Solve

2 x + 3 = 0 : x = - \frac{3}{2}

Solve

x - 4 = 0 : x = 4

The solutions are

x = - 2, x = - \frac{3}{2}, x = 4

2 x^{3} + 6 x^{2} + 5 x + 2 = 0

4 x^{4} + 12 x^{3} + 5 x^{2} = 0

x^{4} - 6 x^{2} + 10 = 0

- 6 x^{3} - 48 x^{2} - 66 x + 120

3 x^{3} - 2 x^{2} - 2 x + 3 = 0

What are the solutions to the equation 2x^3-x^2-22x-24=0 ?
The solutions to the equation 2x^3-x^2-22x-24=0 are x=-2,x=-3/2 ,x=4
Find the zeros of 2x^3-x^2-22x-24=0
The zeros of 2x^3-x^2-22x-24=0 are x=-2,x=-3/2 ,x=4