What are the solutions to the equation roots-6x^3-48x^2-66x+120 ?

The solutions to the equation roots-6x^3-48x^2-66x+120 are x=1,x=-4,x=-5

Find the zeros of roots-6x^3-48x^2-66x+120

The zeros of roots-6x^3-48x^2-66x+120 are x=1,x=-4,x=-5

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roots

- 6 x^{3} - 48 x^{2} - 66 x + 120

x = 1, x = - 4, x = - 5

Solution steps

- 6 x^{3} - 48 x^{2} - 66 x + 120

The roots are the intercepts with the x-axis

(y = 0)

- 6 x^{3} - 48 x^{2} - 66 x + 120 = 0

Factor

- 6 x^{3} - 48 x^{2} - 66 x + 120 : - 6 (x - 1) (x + 4) (x + 5)

- 6 (x - 1) (x + 4) (x + 5) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x - 1 = 0 or x + 4 = 0 or x + 5 = 0

Solve

x - 1 = 0 : x = 1

Solve

x + 4 = 0 : x = - 4

Solve

x + 5 = 0 : x = - 5

The solutions are

x = 1, x = - 4, x = - 5

3 x^{3} - 2 x^{2} - 2 x + 3 = 0

x^{3} + 3 x^{2} - 7 x - 21 = 0

(x^{2} + 7)^{2} = 0

x^{3} - 5 x^{2} + 7 x - 2 = 0

- x^{3} + 6 x^{2} - 10 x + 4 = 0

What are the solutions to the equation roots-6x^3-48x^2-66x+120 ?
The solutions to the equation roots-6x^3-48x^2-66x+120 are x=1,x=-4,x=-5
Find the zeros of roots-6x^3-48x^2-66x+120
The zeros of roots-6x^3-48x^2-66x+120 are x=1,x=-4,x=-5