What are the solutions to the equation -x^3+6x^2-10x+4=0 ?

The solutions to the equation -x^3+6x^2-10x+4=0 are x=2,x=2+sqrt(2),x=2-sqrt(2)

Find the zeros of -x^3+6x^2-10x+4=0

The zeros of -x^3+6x^2-10x+4=0 are x=2,x=2+sqrt(2),x=2-sqrt(2)

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- x^{3} + 6 x^{2} - 10 x + 4 = 0

x = 2, x = 2 + 2, x = 2 - 2

Decimal Notation

x = 2, x = 3.41421 \dots, x = 0.58578 \dots

Solution steps

- x^{3} + 6 x^{2} - 10 x + 4 = 0

Factor

- x^{3} + 6 x^{2} - 10 x + 4 : - (x - 2) (x^{2} - 4 x + 2)

- (x - 2) (x^{2} - 4 x + 2) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x - 2 = 0 or x^{2} - 4 x + 2 = 0

Solve

x - 2 = 0 : x = 2

Solve

x^{2} - 4 x + 2 = 0 : x = 2 + 2, x = 2 - 2

The solutions are

x = 2, x = 2 + 2, x = 2 - 2

4 x^{3} - 12 x^{2} = 0

1 - x - x^{2} + x^{3} = 0

\frac{80}{7} (x^{3}) = 70

2 x^{3} + 54 = 0

3 (x^{2} + 5 x + 1)^{2} + 2 x^{2} + 10 x = 3

What are the solutions to the equation -x^3+6x^2-10x+4=0 ?
The solutions to the equation -x^3+6x^2-10x+4=0 are x=2,x=2+sqrt(2),x=2-sqrt(2)
Find the zeros of -x^3+6x^2-10x+4=0
The zeros of -x^3+6x^2-10x+4=0 are x=2,x=2+sqrt(2),x=2-sqrt(2)