What are the solutions to the equation r^3+2r^2-5r-6=0 ?

The solutions to the equation r^3+2r^2-5r-6=0 are r=-1,r=2,r=-3

Find the zeros of r^3+2r^2-5r-6=0

The zeros of r^3+2r^2-5r-6=0 are r=-1,r=2,r=-3

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r^{3} + 2 r^{2} - 5 r - 6 = 0

r = - 1, r = 2, r = - 3

Solution steps

r^{3} + 2 r^{2} - 5 r - 6 = 0

Factor

r^{3} + 2 r^{2} - 5 r - 6 : (r + 1) (r - 2) (r + 3)

(r + 1) (r - 2) (r + 3) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

r + 1 = 0 or r - 2 = 0 or r + 3 = 0

Solve

r + 1 = 0 : r = - 1

Solve

r - 2 = 0 : r = 2

Solve

r + 3 = 0 : r = - 3

The solutions are

r = - 1, r = 2, r = - 3

2 x^{4} - x^{3} + x^{2} - x - 1

4 x^{3} + 16 x^{2} + 16 x + 12 = 0

x^{3} + x^{2} + 4 = 0

8 x^{3} - 27 = 0

20 = 4 x^{3} - 12 x^{2} - 40 x + 20

What are the solutions to the equation r^3+2r^2-5r-6=0 ?
The solutions to the equation r^3+2r^2-5r-6=0 are r=-1,r=2,r=-3
Find the zeros of r^3+2r^2-5r-6=0
The zeros of r^3+2r^2-5r-6=0 are r=-1,r=2,r=-3