What are the solutions to the equation (x^2+x+1)^2=0 ?

The solutions to the equation (x^2+x+1)^2=0 are x=-1/2+i(sqrt(3))/2 ,x=-1/2-i(sqrt(3))/2

Find the zeros of (x^2+x+1)^2=0

The zeros of (x^2+x+1)^2=0 are x=-1/2+i(sqrt(3))/2 ,x=-1/2-i(sqrt(3))/2

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(x^{2} + x + 1)^{2} = 0

x = - \frac{1}{2} + i \frac{3}{2}, x = - \frac{1}{2} - i \frac{3}{2}

Solution steps

(x^{2} + x + 1)^{2} = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

Solve

x^{2} + x + 1 = 0 : x = - \frac{1}{2} + i \frac{3}{2}, x = - \frac{1}{2} - i \frac{3}{2}

The solutions are

x = - \frac{1}{2} + i \frac{3}{2}, x = - \frac{1}{2} - i \frac{3}{2}

12 x^{3} - 30 x^{2} + 12 x = 0

6 x^{3} + 4 x^{2} - 7 x + 2

r^{3} = 0

(x - 1) (x^{2} + x - 2) = 0

1 - x - x^{3}

What are the solutions to the equation (x^2+x+1)^2=0 ?
The solutions to the equation (x^2+x+1)^2=0 are x=-1/2+i(sqrt(3))/2 ,x=-1/2-i(sqrt(3))/2
Find the zeros of (x^2+x+1)^2=0
The zeros of (x^2+x+1)^2=0 are x=-1/2+i(sqrt(3))/2 ,x=-1/2-i(sqrt(3))/2