What are the solutions to the equation (x-1)(x^2+x-2)=0 ?

The solutions to the equation (x-1)(x^2+x-2)=0 are x=1,x=-2

Find the zeros of (x-1)(x^2+x-2)=0

The zeros of (x-1)(x^2+x-2)=0 are x=1,x=-2

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(x - 1) (x^{2} + x - 2) = 0

x = 1, x = - 2

Solution steps

(x - 1) (x^{2} + x - 2) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x - 1 = 0 or x^{2} + x - 2 = 0

Solve

x - 1 = 0 : x = 1

Solve

x^{2} + x - 2 = 0 : x = 1, x = - 2

The solutions are

x = 1, x = - 2

1 - x - x^{3}

2 x^{3} + (1 - x^{2})^{4} = 0

3 x^{3} + 4 x^{2} + 27 x + 36 = 0

d x^{3}

x^{3} - 3 x^{2} + x - 3 = 0

What are the solutions to the equation (x-1)(x^2+x-2)=0 ?
The solutions to the equation (x-1)(x^2+x-2)=0 are x=1,x=-2
Find the zeros of (x-1)(x^2+x-2)=0
The zeros of (x-1)(x^2+x-2)=0 are x=1,x=-2