What are the solutions to the equation (x^2-3)^2=9 ?

The solutions to the equation (x^2-3)^2=9 are x=sqrt(6),x=-sqrt(6),x=0

Find the zeros of (x^2-3)^2=9

The zeros of (x^2-3)^2=9 are x=sqrt(6),x=-sqrt(6),x=0

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(x^{2} - 3)^{2} = 9

x = 6, x = - 6, x = 0

Decimal Notation

x = 2.44948 \dots, x = - 2.44948 \dots, x = 0

Solution steps

(x^{2} - 3)^{2} = 9

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x^{2} - 3 = 9 : x = 6, x = - 6

Solve

x^{2} - 3 = - 9 : x = 0

The solutions are

x = 6, x = - 6, x = 0

4 x^{3} - 24 x = 0

x^{3} + 6 x^{2} + 15 x - 25 = 0

x^{4} + 4 x^{2}

4 x^{3} + x^{7} = - 5

\frac{7}{18} = 21 x^{6}

What are the solutions to the equation (x^2-3)^2=9 ?
The solutions to the equation (x^2-3)^2=9 are x=sqrt(6),x=-sqrt(6),x=0
Find the zeros of (x^2-3)^2=9
The zeros of (x^2-3)^2=9 are x=sqrt(6),x=-sqrt(6),x=0