What are the solutions to the equation roots x^4+4x^2 ?

The solutions to the equation roots x^4+4x^2 are x=0,x=2i,x=-2i

Find the zeros of roots x^4+4x^2

The zeros of roots x^4+4x^2 are x=0,x=2i,x=-2i

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roots

x^{4} + 4 x^{2}

x = 0, x = 2 i, x = - 2 i

Solution steps

x^{4} + 4 x^{2}

The roots are the intercepts with the x-axis

(y = 0)

x^{4} + 4 x^{2} = 0

Rewrite the equation with

u = x^{2}

and

u^{2} = x^{4}

u^{2} + 4 u = 0

Solve

u^{2} + 4 u = 0 : u = 0, u = - 4

u = 0, u = - 4

Substitute back

u = x^{2},

solve for

x

Solve

x^{2} = 0 : x = 0

Solve

x^{2} = - 4 : x = 2 i, x = - 2 i

The solutions are

x = 0, x = 2 i, x = - 2 i

4 x^{3} + x^{7} = - 5

\frac{7}{18} = 21 x^{6}

x^{3} + 0.1 x^{2} + 0.4 x = 1.2

5 x^{3} - 9 x^{2} + 28 x + 6 = 0

x^{3} + 2 x^{2} - 3 x - 6

What are the solutions to the equation roots x^4+4x^2 ?
The solutions to the equation roots x^4+4x^2 are x=0,x=2i,x=-2i
Find the zeros of roots x^4+4x^2
The zeros of roots x^4+4x^2 are x=0,x=2i,x=-2i