What are the solutions to the equation 2x^3-x^2-6x+3=0 ?

The solutions to the equation 2x^3-x^2-6x+3=0 are x= 1/2 ,x=-sqrt(3),x=sqrt(3)

Find the zeros of 2x^3-x^2-6x+3=0

The zeros of 2x^3-x^2-6x+3=0 are x= 1/2 ,x=-sqrt(3),x=sqrt(3)

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2 x^{3} - x^{2} - 6 x + 3 = 0

x = \frac{1}{2}, x = - 3, x = 3

Decimal Notation

x = 0.5, x = - 1.73205 \dots, x = 1.73205 \dots

Solution steps

2 x^{3} - x^{2} - 6 x + 3 = 0

Factor

2 x^{3} - x^{2} - 6 x + 3 : (2 x - 1) (x + 3) (x - 3)

(2 x - 1) (x + 3) (x - 3) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

2 x - 1 = 0 or x + 3 = 0 or x - 3 = 0

Solve

2 x - 1 = 0 : x = \frac{1}{2}

Solve

x + 3 = 0 : x = - 3

Solve

x - 3 = 0 : x = 3

The solutions are

x = \frac{1}{2}, x = - 3, x = 3

4 x^{7} - 64 x^{3} = 0

r^{3} + 5 r^{2} + 8 r + 4 = 0

5 x^{3} - 2 x^{2} + 20 x - 8

64 x^{3} = 1

z^{4} = - 2 + 0 i

What are the solutions to the equation 2x^3-x^2-6x+3=0 ?
The solutions to the equation 2x^3-x^2-6x+3=0 are x= 1/2 ,x=-sqrt(3),x=sqrt(3)
Find the zeros of 2x^3-x^2-6x+3=0
The zeros of 2x^3-x^2-6x+3=0 are x= 1/2 ,x=-sqrt(3),x=sqrt(3)