What are the solutions to the equation roots 5x^3-2x^2+20x-8 ?

The solutions to the equation roots 5x^3-2x^2+20x-8 are x= 2/5 ,x=2i,x=-2i

Find the zeros of roots 5x^3-2x^2+20x-8

The zeros of roots 5x^3-2x^2+20x-8 are x= 2/5 ,x=2i,x=-2i

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roots

5 x^{3} - 2 x^{2} + 20 x - 8

x = \frac{2}{5}, x = 2 i, x = - 2 i

Solution steps

5 x^{3} - 2 x^{2} + 20 x - 8

The roots are the intercepts with the x-axis

(y = 0)

5 x^{3} - 2 x^{2} + 20 x - 8 = 0

Factor

5 x^{3} - 2 x^{2} + 20 x - 8 : (5 x - 2) (x^{2} + 4)

(5 x - 2) (x^{2} + 4) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

5 x - 2 = 0 or x^{2} + 4 = 0

Solve

5 x - 2 = 0 : x = \frac{2}{5}

Solve

x^{2} + 4 = 0 : x = 2 i, x = - 2 i

The solutions are

x = \frac{2}{5}, x = 2 i, x = - 2 i

64 x^{3} = 1

z^{4} = - 2 + 0 i

x^{3} - 4 x^{2} + 5 x - 2

4 x^{3} - 16 = 0

5 x^{3} = 6 x^{2}

What are the solutions to the equation roots 5x^3-2x^2+20x-8 ?
The solutions to the equation roots 5x^3-2x^2+20x-8 are x= 2/5 ,x=2i,x=-2i
Find the zeros of roots 5x^3-2x^2+20x-8
The zeros of roots 5x^3-2x^2+20x-8 are x= 2/5 ,x=2i,x=-2i